Write the equation for the refractive index of a prism in terms of the angle of minimum deviation $(\delta_m)$ and the angle of the prism $(A)$.

(N/A) For a prism with refractive index $n$, angle of prism $A$, and angle of minimum deviation $\delta_m$, the relationship is given by Snell's Law applied at the minimum deviation condition.
At minimum deviation, the angle of incidence $i$ is equal to the angle of emergence $e$, and the angle of refraction $r_1$ is equal to $r_2 = r = A/2$.
The angle of incidence is given by $i = (A + \delta_m) / 2$.
Using Snell's Law, $n = \frac{\sin(i)}{\sin(r)}$.
Substituting the values, we get the refractive index equation: $n = \frac{\sin((A + \delta_m) / 2)}{\sin(A / 2)}$.